C program to find out G.C.D. of two numbers.

source code


#include<stdio.h>
int main(){
int n1,n2;
printf("\nEnter two numbers:");
scanf("%d %d",&n1,&n2);
while(n1!=n2){
if(n1>=n2-1)
n1=n1-n2;
else
n2=n2-n1;
}
printf("\nGCD=%d",n1);

getch();
return 0;
}

Comments

Post a Comment

Popular posts from this blog

8086 STRING MANIPULATION –FIND AND REPLACE A WORD

ASSUME CS: CODE, DS: DATA DATA SEGMENT LIST DW 53H, 15H, 19H, 02H REPLACE EQU 30H COUNT EQU 05H DATA ENDS CODE SEGMENT START:           MOV AX, DATA                         MOV DS, AX                         MOV AX, 15H                         MOV SI, OFFSET LIST                         MOV CX, COUNT                         MOV AX, 00                         CLD REP                 SCASW             JNZ LOOP                         MOV DI, LABEL LIST             MOV [DI], REPLACE LOOP             MOV AH, 4CH                         INT 21H CODE ENDS END START
Read more

Animated Circles In C++

Source Code #include<stdlib.h> #include<conio.h> #include<graphics.h> #include<dos.h> void main() { int x,y,i; int g=DETECT,d;        initgraph(&g,&d,"\tc\bgi");        cleardevice();        x=getmaxx()/2;        y=getmaxy()/2;        settextstyle(TRIPLEX_FONT, HORIZ_DIR, 3);        setbkcolor(rand());        setcolor(4);        outtextxy(30,100,"Press");        outtextxy(30,130,"any");        outtextxy(30,160,"key");        outtextxy(30,190, "to");        outtextxy(30,220,"Quit");        while (!kbhit())        {        setcolor(rand());        for (int i=0;i<50;i++)        circle(x,y,i );        setcolor(rand());        for (int j=70;j<120;j++)        circle(x,y,j);        setcolor(rand());        for (int k=140;k<190;k++)        circle(x,y,k);        setcolor(rand());        for (int l=210;l<230;l++)        circle(x,y,l);        delay(200);
Read more

C program to find out the sum of series 1 + 2 + …. + n.

source code #include<stdio.h> int main() {     int n,i;     int sum=0;     printf("Enter the n i.e. max values of series: ");     scanf("%d",&n);     sum = (n * (n + 1)) / 2;     printf("Sum of the series: ");     for(i =1;i <= n;i++) {          if (i!=n)               printf("%d + ",i);          else              printf("%d = %d ",i,sum);          }    getch();     return 0; }
Read more