Sum of 1^2 + 2^2 + …. + n^2 series in c programming language

source code


#include<stdio.h>
   int main()
{
    int n,i;
    int sum=0;
    printf("Enter the n i.e. max values of series: ");
    scanf("%d",&n);
    sum = (n * (n + 1) * (2 * n + 1 )) / 6;
    printf("Sum of the series : ");
    for(i =1;i<=n;i++){
         if (i != n)
             printf("%d^2 + ",i);
         else
             printf("%d^2 = %d ",i,sum);
    }
    getch();
    return 0;
}

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C program to find out the sum of series 1 + 2 + …. + n.