C program to convert each digits of a number in words.
source code
#include<stdio.h>
int main()
{
int number,i=0,j,digit;
char * word[1000];
printf("Enter any integer: ");
scanf("%d",&number);
while(number)
{
digit = number %10;
number = number /10;
switch(digit)
{
case 0: word[i++] = "zero"; break;
case 1: word[i++] = "one"; break;
case 2: word[i++] = "two"; break;
case 3: word[i++] = "three"; break;
case 4: word[i++] = "four"; break;
case 5: word[i++] = "five"; break;
case 6: word[i++] = "six"; break;
case 7: word[i++] = "seven"; break;
case 8: word[i++] = "eight"; break;
case 9: word[i++] = "nine"; break;
}
}
for(j=i-1;j>=0;j--)
{
printf("%s ",word[j]);
}
getch();
return 0;
}
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